Detailed explanation coming soon!
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public TreeNode mergeTrees(TreeNode t1, TreeNode t2) {
if(t1 == null && t2 == null) return null;
if(t1 == null) return t2;
if(t2 == null) return t1;
TreeNode mergedTree = new TreeNode(t1.val + t2.val);
mergedTree.left = mergeTrees(t1.left, t2.left);
mergedTree.right = mergeTrees(t1.right, t2.right);
return mergedTree;
}
}
Questions? Have a neat solution? Comment below!